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3 years ago

5

PHYSICS HW HELP PLS!! explain how you got it too thank you! :)

1 answer:

Gnesinka [82]3 years ago

5 0

Answer:

Explanation:

Can you please place the square roots in a proper manner so I may assist you?

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HELP...<br> 3.00 amu = _____ Mev.<br><br> 3.22 x 10-3<br> 2.79 x 103<br> 3.10 x 102

DanielleElmas [232]

The correct answer is:
$2.79 \cdot 10^3 MeV$
Let's see why.

1 amu corresponds to the mass of the proton, which is:
$m_p = 1.66 \cdot 10^{-27} kg$
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
$E=mc^2 = (1.66 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2 = 1.49 \cdot 10^{-10} J$
Now we can convert it into electronvolts:
$E= \frac{1.49 \cdot 10^{-10}kg}{1.6 \cdot 10^{-19} J/eV} =9.34 \cdot 10^9 eV = 934 MeV$

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
$3 amu = 3 \cdot 934 MeV \sim 2790 MeV = 2.79 \cdot 10^3 MeV$

5 0

4 years ago

Read 2 more answers

Which of the following is a part of the digestive system

BlackZzzverrR [31]

The Pancreas

<em>Is an inflammation organ that lies in the lower part of the stomach which plays a big part in the digestive system.</em>

3 0

3 years ago

You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an

a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, $\mu=6\times 10^{-2}$

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

$KE=PE+W$

$\dfrac{1}{2}mv^2=mgh+W$

W is the work done by the friction.

$W=f\times d$

$f=\mu mg\ cos\theta$

$W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}$

$W=\dfrac{\mu mgh}{tan\theta}$

$\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}$

$\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}$

$\dfrac{1}{2}v^2=9.8\times 3.1+\dfrac{6\times 10^{-2}\times 9.8\times 3.1}{tan(30)}$

v = 8.19 m/s

So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0

3 years ago

What is the guage pressure of an object with a mass of 30 kg and 5ft height?

wariber [46]

Answer: D=pg

Explanation:

?????

8 0

3 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

$v_a$ = Relative velocity of ambulance = $109\ km/h=\dfrac{109}{3.6}$

$v_w$ = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

$f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz$

The frequency of sound is 900.48925 Hz

When the wall acts like a source

$f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz$

The frequency of sound is 979.9785 Hz

4 0

3 years ago