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Dmitrij [34]
3 years ago
5

PHYSICS HW HELP PLS!! explain how you got it too thank you! :)

Physics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

Explanation:

Can you please place the square roots in a proper manner so I may assist you?

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An object is five focal lengths from a concave mirror.how do the object and image heights compare?
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An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

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