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Y_Kistochka [10]
3 years ago
6

Cube A has a side length of 3 meters and cube B has a side length of 6 meters. Calculate the volume of the two cubes. Which stat

ement accurately represents the relationship between the two volumes?
Mathematics
1 answer:
Pavel [41]3 years ago
4 0
A = 3 cubed = 27 cubic meters 

B = 6 cubed = 216 cubic meters.


Cube B is 8 times larger than cube A. 
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castortr0y [4]

Answer:

U shaped.

Step-by-step explanation:

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when x = 2 f(x) = -2

x = 3 f(x) = 0

x = 4 f(x) = 6.

So the graphs falls from the left and rises to the right in the form of a U.

You can draw a rough graph to confirm this.

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Totsaken sold half of his comic books and bought ten more. He now has 40. With how many did he begin?
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The answer is 60 because

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8 0
3 years ago
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Suppose that you toss a fair six-sided {1,2,3,4,5,6} die and let X represent the outcome obtained. Find the expected volume of a
timofeeve [1]

Answer:

The expected volume of the box is 364 cubic inches.

Step-by-step explanation:

Since the die is fair, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. Let Y represent the volume of the box in cubic inches. For how the box is formed, Y = X²*24. Thus, the value of Y depends directly on the value of X, and we have

  • (When X = 1) Y = 1²*24 = 24, with probability 1/6 (the same than P(X=1)
  • (When X = 2) Y = 2²*24 = 96, with probability 1/6 (the same than P(X=2)
  • (When X = 3) Y = 3²*24 = 216, with probability 1/6 (the same than P(X=3)
  • (When X = 4) Y = 4²*24 = 384, with probability 1/6 (the same than P(X=4)
  • (When X = 5) Y = 5²*24 = 600, with probability 1/6 (the same than P(X=5)
  • (When X = 6) Y = 6²*24 = 864, with probability 1/6 (the same than P(X=6)

As a consequence, the expected volume of the box in cubic inches is

E(Y) = 1/6 * 24 + 1/6*96 + 1/6*216+ 1/6*384+ 1/6*600+1/6*864 = 364

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3 years ago
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C

Step-by-step explanation:

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