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liberstina [14]
2 years ago
8

Solve equation show work

Mathematics
1 answer:
Naddika [18.5K]2 years ago
7 0

Answer:

h= -8/3

Picture Explanation:

  1. Divide 3 on both sides of the equal sign, as shown above, so (h) can be alone.
  2. Since negative 8, let alone positive 8, can't be divided into 3, you simply leave the fraction as is. So you're left with (h= -8/3)

<em><u>Hope this makes sense.</u></em>

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Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th
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The value of tangent theta is equal to the negative 1.  At this value the value of secant theta is \sqrt{2}.

<h3>What is tangent theta?</h3>

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

Given information-

The value of tangent theta is equal to the negative 1.

\tan \theta=-1

The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

\rm tan\theta=\dfrac{sin \theta}{cos \theta}

The value of tangent theta is equal to the negative 1. Thus put the value in above expression as,

\rm -1=\dfrac{sin \theta}{cos \theta}\\

Simplify it further as,

\rm -cos \theta=sin \theta

When the value of cosine and sine theta is equal, then the angle exist in 4th quadrant with the value of \dfrac{7\pi}{4}. Which extent to the \sqrt{2}/2 for the cosine function.

In the trigonometry cosine theta is the reciprocal of the secant theta. Thus,

\rm \dfrac{1}{sec\theta}=\dfrac{\sqrt{2}}{2}\\sec\theta=\sqrt{2}

Thus the value of secant theta is \sqrt{2}

Learn more about the tangent theta here;

brainly.com/question/29190

4 0
2 years ago
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Dafna1 [17]
Slope (y2-y1)/(x2-x1)
(0-4)/(-5-5) = -4/-10 = 2/5
Y = 2/5x + b
Plug in any point
4 = 2/5(5) + b
4 = 2 + b, b= 2
Final equation: y = 2/5x + 2
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2 years ago
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Please Help I will do Brainliest for first and correct answer
Soloha48 [4]

Answer:

5

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41 - 32 = 9

5/9 x 9 = 5

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3 years ago
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