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suter [353]
3 years ago
6

There is a population of 5,000 bacteria in a colony. If the number of bacteria doubles every 37 minutes, what will the populatio

n be 74 minutes from now?
Mathematics
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

If there are 5000 bacteria in a colony right now, there will be  5000x2, or 10000 bacteria in the colony in 37 minutes.

If there are 10000 bacteria in the colony in 37 minutes, there will be 20000 bacteria in the colony in 74 minutes, as the bacteria doubles every 34 minutes.

Let me know if this helps!

umka2103 [35]3 years ago
8 0

Answer:

20,000

Step-by-step explanation:

74/37=2 so it doubles twice

5,000x2=10,000

10,000x2=20,000

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Answer:

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Step-by-step explanation:

We are not told how to approach this problem.  

One way would be to graph f(x) = x^5 − 10x^3 + 9x on [-3,3] and then to estimate the max and min of this function on this interval visually.  A good graph done on a graphing calculator would be sufficient info for this estimation.  My graph, on my TI83 calculator, shows that the relative minimum value of f(x) on this interval is between x=2 and x=3 and is approx. -37; the relative maximum value is between x= -3 and x = -2 and is approx. +37.  

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Optional:  Another approach would be to use calculus:  we'd differentiate f(x) = x^5 − 10x^3 + 9x, set the resulting derivative = to 0 and solve the resulting equation for x.  There would be four x-values, which we'd call "critical values."

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