Answer:
see below
Step-by-step explanation:
m<Q: 360-68-71-124= 97 degrees
m<Y: 360-95-46-74=145 degrees
m<K: 360-49-89-72=150 degrees
m<R: 360-98-65-69=128 degrees
m<C: 360-77-123-86=74 degrees
m<X: 360-135-105-67=53 degrees
m<T: 360-66-114-92=88 degrees
m<F: 360-146-91-75=48 degrees
First, convert how many yards there were to inches. 3 1/2 yards gets you 126 inches. Next, find out how many inches 2 feet and 10 inches of ribbon is. 34 is your answer. Subtract 34 from 126 to get an answer of 92 inches (7 feet, 6 inches.)
Answer:
-480
Step-by-step explanation:
If f varies directly as g, and inversely as h, then we can write the variation equation:
, where k is the constant of variation.
If g=56 when h=-2 and f=-7, then we substitute these values into the formula to find the value of k.



The equation now becomes:

if f=10 and h=-12, then;


The correct answer is B.
1. area of a pentagon when 1 side is x is

so if perimiter is 100 then one side is 100/5 or 20
area will be

≈<span>688.2 square yards
2. area of a hexagon when 1 side is length x is

so if permiter is 100 then length of one side is 100/6 or about 16.666666666666
the area will be

≈721.7 square yards
3. area of a regular octagon with side lenghts x is

so if 8 sides then side length of each is 100/8 or 12.5
area will be

≈754.4 square yards
octagon wil have most space
you can tell because the more sides it has, the more it gets to a circle and the more area it encloses with a given perimiter
</span>
solution:
we know that ,
u.v = ΙuΙ ΙvΙcosθ
here,
θ =60° (since the given triangle is equilateral triangle)
u.v = ΙuΙ ΙvΙcos60°
= 1 x 1 x 1/2
u.v = 1/2
now, u.w = ΙuΙ ΙwΙcosθ
= ΙuΙ x cos(60x2)
u.w = -1/2