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soldi70 [24.7K]
3 years ago
6

Last option is none of the above

Mathematics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

A and B

Step-by-step explanation:

When rotating a point (or any shape around a certain point), none of the diameters of the shape will change. So for example, with this circle, when you rotate it around a point, the radius and circumference will not change because it has just rotated. It wont be on the x-axis though because point P is not on the x-axis an it is being rotated 180 degrees about point P. Just know that when you are rotating, nothing about the shape changes, all angles or measurements will be the same, it is just moving to a different place.

Hope this helped ^-^

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The table below shows the number of restaurants advertisement in a city directory.
Mnenie [13.5K]
8 + 13 + 14 + 7 = 42

Chinese = 8/42
Simplified = 4/21
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3 years ago
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
Rasek [7]

The area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. It has one pair of opposite congruent angles and the diagonals of a kite are perpendicular.

We have a quadrilateral shown in the picture.

The diagonal divides the quadrilateral into two triangles

The area of the quadrilateral = area of the triangle ADC + area of the

                                                   triangle ADB

= (1/2)3.42×4.39 + (1/2)5.44×3.42

= 7.5069 + 9.3024

= 16.80 square units

Thus, the area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

Learn more about the quadrilateral here:

brainly.com/question/6321910

#SPJ1

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2 years ago
A pitcher allowed 8 runs in 24 innings how many did he allow in 40
vichka [17]
40/5=8

The pitcher allowed 8 runs in 40 innings.
7 0
3 years ago
?
maxonik [38]

Answer:

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3 0
3 years ago
Circle A is shown. Tangents L M and N M intersect at point M outside of the circle. Arc L N is 270 degrees. In the diagram of ci
luda_lava [24]

Answer:

\angle m=90^o

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The measurement of the external angle is the half-difference of the arches that comprise

so

\angle m=\frac{1}{2}(major\ arc\ LN-minor\ arc\ LN)

Remember that the sum of the major arc and a minor arc is equal to 360 degrees

we have

major\ arc\ LN=270^o ----> is given

so

minor\ arc\ LN=360^o-270^o=90^o

substitute the values

\angle m=\frac{1}{2}(270^o-90^o)=90^o

5 0
4 years ago
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