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Gnoma [55]
2 years ago
12

graph the relation of the table shown. is the relation a function why or why not? (x,y) (-1,3),(-1,2),(0,-4),(4,2)

Mathematics
1 answer:
marusya05 [52]2 years ago
4 0

Answer:

It is not a function.

Step-by-step explanation:

This is not a function, because there is more than one y value when x = -1.  A function has one value for each x value.

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3 years ago
Solve for C.<br> -5/8c=20
iris [78.8K]
-5/8c = 20....multiply both sides by -8/5 (this cancels out the -5/8 on the left
c = 20(-8/5)
c = -160/5
c = - 32

check..
-5/8(-32) = 20
160/8 = 20
20 = 20 (correct)

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8 0
3 years ago
Please help meee im being timed on thisss
sattari [20]

Answer:

y=0.25x

We can think of k as an unknown number.

8×_=2.00

12×_=3.00

20×_=5.00

If we divide 2 with 8 we are left with 0.25.

It's the same for the other numbers so we know the constant is 0.25.

When we use the formula y=0.25x with the numbers above, it is correct.

8×0.25=2.00

12×0.25=3.00

20×0.25=5.00

4 0
3 years ago
Name the algebraic property demonstrated in the example below: (1 point) 4(x + y) = 4x + 4y
svet-max [94.6K]

Answer:

distributive property

Step-by-step explanation:

distributive property, because 4 carries over to each variable and then the two product are added.

4(x+y)=4x+4y

6 0
3 years ago
What the power a when 5^a = 1/125
Advocard [28]

Answer:

a = -3

General Formulas and Concepts:

<u>Algebra I</u>

  • Solving Exponential Equations
  • Exponential Property [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 5^a = \frac{1}{125}<em />

<em />

<u>Step 2: Solve for </u><em><u>a</u></em>

  1. Rewrite:                                                                                                                \displaystyle 5^a = \frac{1}{5^3}
  2. Rewrite [Exponential Property - Rewrite]:                                                       \displaystyle 5^a = 5^{-3}
  3. Set:                                                                                                                    \displaystyle a = -3
3 0
2 years ago
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