Answer: =4.4n-13
Step-by-step explanation:
Let's simplify step-by-step.
2n−9−(−2.4n+4)
Distribute the Negative Sign:
=2n−9+−1(−2.4n+4)
=2n+−9+−1(−2.4n)+(−1)(4)
=2n+−9+2.4n+−4
Combine Like Terms:
=2n+−9+2.4n+−4
=(2n+2.4n)+(−9+−4)
=4.4n+−13
Tan(-180)=0 the answer is 0.
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Which statement is true about this data set? {43, 46, 48, 57, 42, 47, 48, 44, 46, 45, 48}
vfiekz [6]
Answer: D) 57
Step-by-step explanation:
Answer:
option C
Step-by-step explanation:
