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nika2105 [10]
3 years ago
11

3384/24 step by step ......I really need help

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0
Don’t think this is reliable anyone can type stuff down so I wouldn’t recommend it
You might be interested in
Solve for X<br> Your answer must be simplified.<br><br> -7x &gt; 10
Bezzdna [24]

Answer:

There are many solution for this problem

The solutions are -2, -3, -4..... And even fractions like -11/7, -12/7, etc.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Is 12cm greater than less than or equal to 98mm
dmitriy555 [2]
There are 10 millimeters in a centimeter, so to find the amount of centimeters that 98mm is equal to, you do this:

98/10 = 9.8

9.8 is a smaller number than 12, so your answer is greater.
4 0
4 years ago
Simplify 10 - [14 = (3 + 4) · 2]+3
lora16 [44]

Answer:

There is a typo near the equal sign.

There can be two different answers if we think that = sign as + or -.

First way: Making = as +

=> 10 - [14 + (3+4) x 2] +3

=> 10 - [14 + 7 x 2] + 3

=> 10 - [14 + 14] + 3

=> 10 - 28 + 3

=> 10 + 3 - 28

=> 13 - 28

=> -15

=> So, -15 is the answer if we consider "=" sign as "+" sign.

Second way: Making = as -

=> 10 - [14 - (3+4) x 2] + 3

=> 10 - [14 - 7 x 2] + 3

=> 10 - [14 - 14] + 3

=> 10 - 0 + 3

=> 10 + 3

=> 13

=> So, 13 is the answer if we consider "=" sign as "-" sign.

5 0
3 years ago
Z varies jointly with x, and y, and z=7 when x= 2, y= 2
fomenos

Answer:

56

Step-by-step explanation:

Complete question:

Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)

If z varies jointly with x, and y, this is expressed as;

z = kxy

If z=7 when x= 2, y= 2

7  = k(2)(2)

7 = 4k

k = 7/4

To get z when x= 4 and y = 8

z = kxy

z =7/4 (4)(8)

z = 7*8

z = 56

Hence the value of z is 56

7 0
3 years ago
What is the value of x in the solution to this system of equation 3x-5y=22: y=-5x+32
galina1969 [7]

Answer:

x= 33/7 or 4.7

Step-by-step explanation:

3 0
3 years ago
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