Answer:
$81.55
Step-by-step explanation:
$15+15%=15x1.15=$17.25
$23+10%=23x1.1=$27.50
$32+15%=32x1.15=$36.80
Total=$81.55
(Time to find a cheaper shop)
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
3^-2 = 0.111111111 ← Answer
So firstly, multiply both sides by t: 
Next, add both sides by v0, and your answer will be: 
Step-by-step explanation:
A is in Quadrant I
D is in Quadrant III