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adelina 88 [10]
3 years ago
9

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mathematics
1 answer:
Mariulka [41]3 years ago
3 0

Answer:

<em>Two possible answers below</em>

Step-by-step explanation:

<u>Probability and Sets</u>

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

\displaystyle P=\frac{19}{29}

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

\displaystyle P=\frac{17}{29}

P = 0.59

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95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.

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Data: 5, 15, 12, 22, 27

mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months

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critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776

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The Value of x in the system of equation at the right is -2 what is the value of a? use elimination to help you find the value.
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--------------------
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