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3 years ago

10

Maricruz prepared 450 ml of 0.0085 M solution of sodium chloride. How many grams of NaCl did she need to make 0.450 L of 0.0085

M NaCl?

1 answer:

Anton [14]3 years ago

8 0

Answer:

Explanation:

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Which of the following could be considered a scientific method? 01.01 the science of chemistry

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Answer:

a) the ability to extend the theory to make predictions

b) it is explanatory

Explanation:

Could be a Hallmark of a Scientific Theory: a & b

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In which state of matter are the particles at rest (not moving at all)?

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Solids for sure

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Equation below is used to determine the heat flux for convection

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Q=hc A (Ts-Ta)
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3 years ago

A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is

Andre45 [30]

Answer:

525°C is the maximum safe operating temperature the engineer should recommend for this reaction.

Explanation:

Volume of the cylindrical container = V = $\pi r^2h$

Height of the vessel = h =60.0 cm

Diameter of the vessel = d = 50.0 cm

Radius of the vessel = r = 0.5d = 25.0 cm

$V=3.14\times (25.0 cm)^2\times 60.0 cm=117,809.72 cm^3=117,809.72mL$

$1 cm^3=1 mL$

1 mL = 0.001 L

117,809.72 mL = 117,80972 L ≈ 118 L

Pressure of the gas in vessel = P = 7.40 MPa = $7.40\times 10^6 Pa$

$1 MPa = 10^6 Pa$

1 atm = 101325 Pa

$P=\frac{7.40\times 10^6}{101325} atm=73.0 atm$

Mass sulfur hexafluoride gas = 19.2 kg = 19200 g

1 kg = 1000 g

Moles of sulfur hexafluoirde = $\frac{19200 g}{146 g/mol}=131.5 mol$

Temperature of the gas in vessel = T

Using an ideal gas equation :

$PV=nRT$

$T=\frac{PV}{nR}=\frac{73.0 atm\times 118 L}{0.0821 atm L/mol K\times 131.5 mol}$

T = 797.8 ≈ K 798 K

T = 798 - 273°C = 525°C

525°C is the maximum safe operating temperature the engineer should recommend for this reaction.

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3 years ago

For the reaction 2H 2 +O 2 2H 2 O calculate the percent yield if 860. of water is produced when 100. g of hydrogen react with an

-BARSIC- [3]

The percent yield : 95%

<h3> Further explanation </h3>

Given

Reaction

2H₂+O₂ ⇒2H₂O

Required

The percent yield

Solution

mol of Hydrogen(as a limiting reactant) :

$\tt \dfrac{100}{2}=50$

mol H₂O based on H₂ , and from equation mol ratio H₂:H₂O=2 : 2, so mol H₂O = 50

Mass of water(theoretical yield) :

$\tt mass=50\times 18=900~g$

$\tt \%yield=\dfrac{860}{900}\times 100\%=95\%$

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2 years ago