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LekaFEV [45]
2 years ago
10

Maricruz prepared 450 ml of 0.0085 M solution of sodium chloride. How many grams of NaCl did she need to make 0.450 L of 0.0085

M NaCl?
Chemistry
1 answer:
Anton [14]2 years ago
8 0

Answer:

Explanation:

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Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% N
olga nikolaevna [1]

Answer:

π = 14.824 atm

Explanation:

wt % = ( w NaCL / w sea water ) * 100 = 3.5 %

assuming w sea water = 100 g = 0.1 Kg

⇒ w NaCl = 3.5 g

osmotic pressure ( π ):

  • π = C NaCl * R * T

∴ T = 20 °C  + 273 = 293 K

∴ C ≡ mol/L

∴ density sea water = 1.03 Kg/L....from literature

⇒ volume sea water = 0.1 Kg * ( L / 1.03 Kg ) = 0.097 L sln

⇒ mol NaCl = 3.5 g NaCL * ( mol NaCL / 58.44 g ) = 0.06 mol

⇒ C NaCl = 0.06 mol / 0.097 L = 0.617 M

⇒ π = 0.617 mol/L * 0.082 atm L / K mol * 293 K

⇒ π = 14.824 atm

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3 years ago
What is the wavelength, in nm, of the light photon emitted by a hydrogen atom when an electron goes from n
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Hence, the wavelength of the photon associated is 1282 nm.

Explanation:

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2 years ago
Interpret, in terms of atoms and in terms of moles, the supscript in a chemical formula  C2H6
tigry1 [53]
Carbon (24.00)(2)+hydrogen(1.01)(6)
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The molecular structure of water contains two atoms of hydrogen and one atom of oxygen. When water reaches its boiling point and
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The water reaches its boiling point and turns into water vapor. This process is a physical change. The change is substance status. And the physical change will not destroy the molecular structure. So the molecular structure will not change.
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During a titration the following data were collected. A 20.0 mL portion of solution of an unknown acid HX was titrated with 2.0
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Answer:

The molarity of the acid HX is 6.0 M.

Explanation:

We determine the amount of moles of KOH used to neutralize the acid:

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Then, we calculate the amount of moles of acid:

0.12 moles KOH×\frac{1 mole HX}{1 moles KOH}=0.12 moles HX

The molarity of HX is:

\frac{0.12 moles HX}{20ml} *\frac{1000ml}{1l}=6.0 M

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