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Novay_Z [31]
3 years ago
13

Give an example of a mineral that is an element and a mineral that is not an element.

Chemistry
1 answer:
kow [346]3 years ago
3 0
A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. Minerals may be metallic, like gold, or nonmetallic, such as talc.
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Which of the following occurs when a reaction in a solution is at equilibrium and
romanna [79]

Equilibrium shifts to produce more reactant.

8 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?
GalinKa [24]

Answer:

B. Cu (s) +Ni(NO3)2 (aq) - 2CuNO3 +Ni (s)

Explanation:

the above reaction is a substitution reaction

7 0
3 years ago
The faster the particles, the
otez555 [7]

Answer:

When for example, heating up an ice cube the particles of the ice start to vibrate fast enough to get separated into liquid caused from high temperature. So the answer is Higher.

4 0
3 years ago
What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

3 0
3 years ago
In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 29.43 mL of 0.1973 M NaOH is added to a 32.
Tamiku [17]
            moles NaOH = c · V = 0.1973 mmol/mL · 29.43 mL = 5.806539 mmol
            moles H2SO4 = 5.806539 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.9032695 mmol
Hence
            [H2SO4]= n/V = 2.9032695 mmol / 32.42 mL = 0.08955 M
The answer to this question is  [H2SO4] = 0.08955 M

6 0
3 years ago
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