3 years ago

Another 100 XDDDDD take em

Mathematics

2 answers:

pychu [463]3 years ago

8 0

XDDDDDDDDDDDDDDDDDDDD

allsm [11]3 years ago

7 0

Answer:

thanks yo so much. appreciated it

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Correct answer will get Brainliest.

IRINA_888 [86]

Answer:

Step-by-step explanation:

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3 years ago

The answer to if he was right or not

Kryger [21]

Answer:

Incorrect

Step-by-step explanation:

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3 years ago

A rocket is launched vertically from the ground with an initial velocity of 64 ft/sec.

diamong [38]

we know the rocket was launched from the ground, meaning its initial height is 0, thus

$~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&64\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&0\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t$