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3 years ago

Determine the domain and the range for this relationship.

Mathematics

1 answer:

VMariaS [17]3 years ago

6 0

Not enough information provided

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8.8 more than the quotient of five and X

Bezzdna [24]

Step-by-step explanation:

8.8 more than the quotient of five and X

Solution,

$8.8 + \frac{5}{x}$

3 0

3 years ago

If the population of a city is 8,839,469 then declines by 4% every year, what is the population in 3 years?

quester [9]

8,839,469 people* 94% percent of last years population= 8,309,101 people after 1 year
8,309,101 people*94% percent of last years population= 7,810,555 people after 2 years
7,810,555 people*94% percent of last years population= 7,341,922 people after 3 years

7 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago

Look at picture for question

netineya [11]

Answer:

The radius is 25 in., circumference is 207

Step-by-step explanation:

Please mark as Brainliest! :)

Have a nice day.

7 0

3 years ago

Write a linear equation that contains the ordered pair shown in the table below:

Nutka1998 [239]

Did anyone get the answer??

7 0

3 years ago