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vitfil [10]
3 years ago
9

Starting at the same point, Tom and Juanita go biking in opposite directions. If Tom rides at a speed of 18 mph, and Juanita rid

es at a speed of 16 mph, how far apart will they be in 2 hours?
A.
50 miles
B.
34 miles
C.
68 miles
D.
78 miles
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

it's answer is C 68 miles

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If 10 miles is about 16 kilometers and the distance between two towns is 45 miles use a ratio table to find the distance between
cricket20 [7]
   10 miles              45 miles
-----------------  *  ---------------------   Cross Multiply
16 kilometres       x kilometres

10 x = 720

x = about 72 kilometres
4 0
3 years ago
A ladder leans against a building. The angle of elevation of the ladder is 70°. The top of the ladder is 25 ft from the ground.
jeyben [28]
Sine rule

a/Sin(A) = b/Sin(B) = c/Sin(C)
     b
 C / |
a / _| A 
    B  c

We know that a = 70 degrees and A = 25 foot
So 70/Sin(25) = Something
We also know we want C, and that c = 90 degrees
So 70/Sin(25) = 90/Sin(C)
Then you have to rearrange the equations. Start with Multiply all by Sin(C)
So [Sin(C)][70/Sin(25)] = 90
Then divide everything by 70/Sin(25)
So Sin(C) = 90/[70/Sin(25)]
Now you want to isolate C, so Sin-1 everthing
So C = Sin-1{90/[70/Sin(25)]}
So C = 32.91309534
To the nearest tenth, 32.9ft
Hope that helps :)
4 0
3 years ago
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What amount of heat is required to raise the temperature of 5 kg of water through 20° c?<br>​
allochka39001 [22]

Answer:

420,000 J/Kg

Step-by-step explanation:

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energy= 20*5*4200

energy= 420,000

7 0
3 years ago
The length of each side of a square is 3 inches more than the length of each side of a small square. The sum of the areas of the
NeX [460]

Answer:

\text{Smaller square's 15 inches, Bigger square's 18 inches}

Step-by-step explanation:

GIVEN: The length of each side of a square is 3 inches more than the length of each side of a small square. The sum of the areas of the square is 549 inches.

TO FIND: the lengths of the sides of the two squares.

SOLUTION:

let the length of side of small square be \text{x}

Area of small square =(\text{side})^2=\text{x}^2

As length of each side of bigger square is 3\text{ inches} more than the smaller square

length of side of bigger square =\text{x}+3\text{ inches}

Area of bigger square =(\text{x+3})^2

Also

Sum of areas of both square =549\text{ inch}^2

(\text{x})^2+(\text{x+3})^2=549

2\text{x}^2+6\text{x}+9=549

\text{x}^2+3\text{x}-270=0

\text{x}=15,-18

as the length of side can never be negative

\text{x}=15

length of side of smaller square =15\text{ inches}

length of side of bigger square =\text{x}+3\text{ inches}=18\text{ inches}

Hence the length of smaller and bigger square are 15\text{ inches} and 18\text{ inches} respectively.

7 0
3 years ago
What are the solution(s) of the quadratic equation 98 – x2 = 0? x = x = x = no real solution
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I hope this helps you

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