Answer:
The value is 
Explanation:
From the question we are told that 
     The mass of the object is  
     The unstressed length of the string is  
     The length of the spring when it is  at equilibrium is  
       The initial speed (maximum speed)of the spring when given a downward blow 
 Generally the maximum speed  of the spring  is mathematically represented as 
            
Here A is maximum height above the floor (i.e the maximum amplitude)
             and  is the angular frequency which is mathematically represented as
 is the angular frequency which is mathematically represented as 
        
So 
         
=>      
Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as 
            
=>         
=>         
Generally at equilibrium position the net force acting on the spring is  
             
=>         
=>        
So 
             
=>          
 
        
             
        
        
        
Given Information:
Length of wire = 132 cm = 1.32 m
Magnetic field = B =  1 T
Current = 2.2 A
Required Information:
(a) Torque = τ = ?
(b) Number of turns = N = ?
Answer:
(a) Torque = 0.305 N.m
(b) Number of turns = 1
Explanation:
(a) The current carrying circular loop of wire will experience a torque given by 
τ = NIABsin(θ)   eq. 1
Where N is the number of turns, I is the current in circular loop, A is the area of circular loop, B is the magnetic field and θ is angle between B and circular loop. 
We know that area of circular loop is given by
A = πr²
where radius can be written as
r = L/2πN
So the area becomes
A = π(L/2πN)²
A = πL²/4π²N²
A = L²/4πN²
Substitute A into eq. 1
τ = NI(L²/4πN²)Bsin(θ)
τ = IL²Bsin(θ)/4πN
The maximum toque occurs when θ is 90°
τ = IL²Bsin(90)/4πN
τ = IL²B/4πN
torque will be maximum for N = 1 
τ = (2.2*1.32²*1)/4π*1
τ = 0.305 N.m
(b) The required number of turns for maximum torque is
N = IL²B/4πτ
N = 2.2*1.32²*1)/4π*0.305
N = 1 turn
 
        
             
        
        
        
The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.
        
                    
             
        
        
        
Answer and Explanation:
a. An oxygen-filled balloon is not able to float in the air, because the oxygen inside the balloon is of the same density, that is, the same "weight" as the oxygen outside the balloon and present in the atmosphere. The balloon can only float if the gas inside it is less dense than atmospheric oxygen. Helium gas is less dense than atmospheric gas, so if a balloon is filled with helium gas, that balloon will be able to float because of the difference in density.
b. The ship is able to float in the water because its steel construction is hollow and full of air. This makes the average density of this ship less than the density of water, which makes the ship lighter than water and for this reason, this ship is able to float. In addition, the ship is partially immersed, allowing the weight of the ship on the water to counteract the buoyant force that the water promotes on the ship. Weight and buoyant are two opposing forces that keep the ship afloat.