The circle on the left shows a magnified view of a very small portion of liquid water in a closed container. What would the magn
2 answers:
<em><u>The magnified view of the portion of the container will show a very less number of molecules of water (not in the form of hydrogen and oxygen separately) because the water is converted to gaseous form.</u></em>
Explanation:
The water can exist in all the three states of matter. It exists as solid in the form of ice at the temperature below , as liquid in the form of water in the temperature range of
and as gas in the form of steam or vapor the the temperature above
.
The magnified view of the container having water will have the fairly enough number of the water molecule as the combination of the one oxygen and two hydrogen atoms.
The magnified view of the water vapor present in the container will show a very small number of the atoms of water as the gas molecules are at a comparatively larger distance from one another. but the molecules of water will not be broken into their atoms separately.
Thus, <em><u>The magnified view of the portion of the container will show a very less number of molecules of water (not in the form of hydrogen and oxygen separately) because the water is converted to gaseous form.</u></em>
<em><u></u></em>
Learn More:
1. Similarities between longitudinal and transverse waves brainly.com/question/3293068
2. Consequence of third law of thermodynamics brainly.com/question/3564634
3. how does the reflection differ from the refraction and diffraction brainly.com/question/3183125
Answer Details:
Grade: High School
Subject: Physics
Chapter: State of Matter
Keywords:
water, evaporates, ice, solid, vapor, liquid, temperature, gas, molecules, hydrogen, magnified, small portion, closed container.
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Answer:
ac = 72 m/s²
Fc = 504 N
Explanation:
We can find the centripetal acceleration of the hammer by using the following formula:
where,
ac = centripetal acceleration = ?
v = constant speed = 12 m/s
r = radius = 2 m
Therefore,
<u>ac = 72 m/s²</u>
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Now, the centripetal force applied by the athlete on the hammer will be:
<u>Fc = 504 N</u>
Answer:
The total power they will consume in series is approximately 2.257 W
Explanation:
The connection arrangement of the headlight and the engine starter = Parallel to the battery
The voltage of the battery, V = 12.0 V
The power at which the headlight operates in parallel, = 38 W
The power at which the kick starter operates in parallel, = 2.40 kW
We have;
P = V²/R
Where;
R = The resistance
V = The voltage = 12 V (The voltage is the same in parallel circuit)
For the headlight, we have;
R₁ = V²/ = 12²/38 = 72/19
R₁ = 72/19 Ω
For the kick starter, we have;
R₂ = V²/ = 12²/2.4 = 60
R₂ = 60 Ω
When the headlight and kick starter are rewired to be in series, we have;
Total resistance, R = R₁ + R₂
Therefore;
R = ((72/19) + 60) Ω = (1212/19) Ω
The current flowing, I = V/R
∴ I = 12 V/(1212/19) Ω = (19/101) A
We note that power, P = I²R
In the series connection, we have;
= I² × R₁
∴ = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W
The power at which the headlight operates in series, ≈ 0.134 W
= ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W
The power at which the kick starter operates in series, ≈ 2.123 W
The total power they will consume, =
+
Therefore;
≈ 0.134 W + 2.123 W = 2.257 W