Answer:
he tail of the arrow moves a distance of 0.5 m as the arrow is shot. yare yare daze
Explanation:
Answer:
Explanation:
Givens
d = 115 km
r = 80 km/hr
t = ?
Equation
d = r*T
Solution
115 = 80 * t Divide by 80
115/80 = t
t = 1.4375 hours.
Answer:
We want to describe how to graph a linear equation.
Explanation:
The given equation is:
y = -4x - 1
a) To graph it, we need to find two points that belong to the line, then we graph the points, and then we connect them with a line.
To get the points, we just need to evaluate the function in two different values of x.
for x = 0
y = -4*0 - 1 = -1
So we have the point (0, -1)
for x = 1
y = -4*1 - 1 = -5
So we have the point (1, - 5)
Now we just need to find these two points and connect them with a line, the graph can be seen below.
b) To check if the graph is correct we can see two things:
in y = -4*x - 1
The y-intercept is -1, this means that the graph should intersect the y-axis at y = -1
The slope is -4, this means that for each unit increase on x, we should see that the y-value decreases by 4.
Checking those two things we can see if our graph is correct or not.
pls give brainliest!
Answer:
The propulsion force at the moment of departure, is 49 N
Explanation:
Given;
diameter of tubes = 5 cm = 0.05 m
volumetric flow rate, V = 50 L/s = 0.005 m³/s
density of water, ρ = 1000 Kg /m³
hydraulic / propulsion force, F = ρVg
where;
ρ is the density of the fluid (water)
V is the volumetric flow rate of water
g is acceleration due to gravity
propulsion force, F = ρVg
propulsion force, F = 1000 x 0.005 x 9.8
propulsion force, F = 49 N
Therefore, the propulsion force at the moment of departure, is 49 N
Answer/solution:
Given :
Mass =5kg
T 1 =20 C,T 2 =100 ∘C
ΔT=100−20=80 ∘C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ