Answer:
x ≈ 11.5° or 168.5°
Step-by-step explanation:
csc² x − 5 csc x = 0
Factor:
csc x (csc x − 5) = 0
Set each factor to 0 and solve:
csc x = 0
sin x = undefined
no solution
csc x − 5 = 0
csc x = 5
sin x = 1/5
x = arcsin(1/5)
x ≈ 11.5° or 168.5°
Answer:
Type I error:
a. The rainfall is minimal enough to operate safely, and the ride is shut down.
Type II error:
d. The rainfall is too heavy to operate safely, and the ride continues to operate.
Step-by-step explanation:
In this case:
The null hypothesis (H0) states that mean rainfall is minimal
The alternative hypothesis (H1) states that mean rainfall is heavy.
A type I error occurs if one rejects the null hypothesis when it is actually true.
In this case; if the rainfall is minimal enough to operate safely and the ride is shut down is an example of Type I error because the null hypothesis is true and it is rejected.
A type II error occurs if one does not reject the null hypothesis when it is false, that is one accept the null hypothesis when it is false.
In this case; the null hypothesis is false and it is accepted is an example of type II error. So, the rainfall is too heavy to operate safely (means null hypothesis is false) and the ride continues to operate (means the null hypothesis is accepted when it is false).
Unfortunately, you haven't shared the equations from which you're supposed to choose your answer.
But we can write our own.
When will the distance traveled by the 1st car = the distance traveled by the 2nd car?
55 miles + (55 mph)x = (60 mph)x
solve this for x: 55 miles = (60-55)x mph = 5 mph
x=11 hours
The two cars are the same distance from the starting point after 11 hours.
The first term is 138
The difference is 55
The iterative rule for the amount of money Mr Speas has after n weeks is
55/2 n² + 221/2 n
During the first week she has $138 in his bank account. At the end of each week she deposited $55 into her bank account.
The first term will be 138 .
The common difference is 55 because her bank always increase by $55 dollars every week. The sequence will be 138, 193, 248, 303, 358...…
The difference = 193 - 138 = 55.
The iterative rule for the amount of money Mr Speas has after n weeks can be represented below
n = number of weeks
a = first term = 138
d = common difference = 55
Using AP formula,
sₙ = n/2(2a + (n - 1)d)
sₙ = n/2 (2(138)+ (n - 1)55)
sₙ = n /2(276 + 55n -55)
sₙ = n /2(221 + 55n)
sₙ = 55/2 n² + 221/2 n
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