Enter the value of 6.(2+15) - 3. X 2 3 1 6 5 4 9 8 hurry in state test need now
1 answer:
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Answer:
1035.33 feet
Step-by-step explanation:
OBH is a triangle and the sum of the angles of a triangle = 180
∠OBH = 90°
∠OHB = 180 -(49 + 90) = 41°
The law of sines that the ratio of each side of a triangle to the sin of the angle opposite it is the same
Thus
A/sinα = B/sinβ = C/sinγ
where A, B and C are the three sides of the triangle and α, β, γ corresponding respectively to the angles opposite them.
Using the law of sines
Therefore BH which is the height the helicopter is flying at is
≈ 1035.33 feet
the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7
<u>Step-by-step explanation:</u>
Here we have , to find the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake . Let's find out:
We know that , Value of earthquake is given by formula
⇒ , Where M is magnitude of earthquake
is the measured magnitude of intensity of earthquake .
is the standard magnitude of intensity of earthquake .
According to question , , Hence
⇒
⇒
⇒
⇒ { On rounding off we get }
⇒
Therefore , the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7