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Tems11 [23]
3 years ago
14

Garry is studying a square pyramid and wants to draw a net of the figure to help determine its surface area. Which net represent

s a square pyramid?
A net with a triangular base and 3 square sides.
A net with a square base, 2 triangular sides, and 2 square sides.
A net with a square base and 4 triangular sides.
A net with a square base, 2 triangular sides, and 4 square sides.
Mathematics
2 answers:
notka56 [123]3 years ago
8 0

Answer:

A net with a square base and 4 triangular side

Step-by-step explanation:

drek231 [11]3 years ago
8 0

Answer: the answer is C

Step-by-step explanation:

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List 3 values that would make this inequality true 8+y>11
alina1380 [7]
You could use so many for example 4, 10, 57, 5729, any number above 4 would work since that plus 8 would be greater than 11
4 0
3 years ago
Please help thank you
daser333 [38]

Answer:

21

Step-by-step explanation:

Add 34 to both sides.

14x = 11x + 63

Subtract 11x from both sides

3x = 63

Divide both sides by 3

21

Hope I helped :)

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3 years ago
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madreJ [45]

Answer:

the answer is A 90+0.25x=147.50

Step-by-step explanation:

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7 0
3 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
Find m a. 26<br> b. 36 <br> c. 56<br> d. 34
dusya [7]
The answer is c or b
6 0
3 years ago
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