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Sliva [168]
3 years ago
13

I’ll mark u as brainlist if u get this right!!

Mathematics
2 answers:
WITCHER [35]3 years ago
6 0

Answer:

A

Step-by-step explanation:

When X is less than -1, positive parabola.  

jonny [76]3 years ago
3 0
I agree, (just to give a second opinion) It is A
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HELP PLEASEEEEEEEEEEEEE
Colt1911 [192]

Answer:

-5.04199038

Step-by-step explanation:

(y2-y1)/(x2-x1)

Plus, mthway can double check

8 0
2 years ago
An isosceles trapezoid is a quadrilateral with two congruent legs, a pair of parallel bases, and congruent base angles. Prove th
seraphim [82]

Answer:

The answer is below

Step-by-step explanation:

We must first define the concepts a little:

We have that when the sides are congruent that is to say that they have the same direction and the same size and also the two opposite sides are parallel, the angles will be the same.

Now, in an isosceles triangle, two angles are congruent, because their two sides are congruent.

3 0
3 years ago
Use the data in the table to write a multiplication story for the number fact. Solve 2x6=
Afina-wow [57]
6*2=12.
You have not included a table so I assume this is the answer you want.
4 0
3 years ago
A name brand cereal is on sale and costs $4.50 for an 18.2oz box. The great value brand version of the cereal costs $4.03 for a
KengaRu [80]

Answer:

You do 4.50 divided by 18.2 and that equals 0.25 cents Pero oz and then you do 4.03 divided by 13.1 which that equals 0.31 cents per oz which that would mean the name brand cereal that’s on sale cost less Per oz

6 0
3 years ago
The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is
aniked [119]

Answer:

10.50°C

Step-by-step explanation:

Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3

The rate of change in temperature of the bug path can be expressed using the composite formula:

dT/dt = Tx(dx/dt) + Ty(dy/dt)

If x = 2+t; dx/dt = 1

If y = 1+12t; dy/dt = 1/2

Substituting the parameters gotten into dT/dt we will have;

dT/dt = 9(1)+3(1/2)

dT/dt = 9+1.5

dT/dt = 10.50°C/s

Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s

7 0
3 years ago
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