Answer:
Geometric and a common ratio of 7
Step-by-step explanation:
I found this out by dividing all the number and for each time I divided. I always got 7
Ex. 21÷3, 3÷3/7, 3/7÷3/49
Hope this helped
Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).
TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.
Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,
PQ^2 + QR^2 = PR^2
PQ^2 + 5^2 = 9^2
PQ^2 = 56
PQ = √56 = 2√14
Then the perimeter of PQRS is
PQ + QR + RS + SP = 2√14 + 5 + 5 + 2√14 = 10 + 4√14
and so the answer is B.
Answer:
- Yes, diagonals bisect each other
Step-by-step explanation:
<em>See attached</em>
Plot the points on the coordinate plane
Visually, it is seen that the diagonals bisect each other.
We can prove this by calculating midpoints of AC and BD
<u>Midpoint of AC has coordinates of:</u>
- x = (1 - 1)/2 = 0
- y = (4 - 4)/2 = 0
<u>Midpoint of BD has coordinates of:</u>
- x = (4 - 4)/2 = 0
- y = (-1 + 1)/2 = 0
As per calculations the origin is the bisector of the diagonals.
Answer:
x=11
Step-by-step explanation:
7x-9-4(x-1)=28
7x-9-4x+4=28
3x-5=28
3x=33
x=11