Answer:
See the answer below
Explanation:
For each heterozygous parent with the genotype BbRr, the possible gametes are: BR, Br, bR, and br. A set of these gametes from one of the parents will be lined up along the top of the Punnet's square while another set from the other parent will be lined up along the side of the square.
The result is shown in the attached image.
Answer:
If the trait for tall and trait for yellow are recessive: ttyy and ttyy
If the trait for tall is dominant and trait for yellow is recessive: TTyy and TTyy, Ttyy and TTyy
If the trait for tall is recessive and trait for yellow is dominant: ttYY and ttYY, or TtYy and TTYY
If the trait for tall is dominant and trait for yellow is dominant TTYY and TTYY, or TtYy and TTYY
Answer:
B is the answer of this question
Answer:
6CO2 + 6H2O →(Light energy)→ C6H12O6 + 6O2
Explanation: