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GaryK [48]
2 years ago
10

15,000,015,969+5,000,003

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0
<h2>Answer:</h2><h2>15,005,015,972</h2><h2></h2><h2>Hope this helps!!</h2>
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The number of hours a lightbulb burns before failing varies from bulb to bulb. The population distribution of burnout times is s
liubo4ka [24]

ANSWER:

The average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

STEP-BY-STEP EXPLANATION:

The cental limit theorem states, that id the sample size is large (30 or more), then the sampling distribution of the sample means is approximately normal with mean ц and standar deviation б/\sqrt{n}

Thus the correct answer is the average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

6 0
3 years ago
Which three lengths could be the lengths of the sides of a triangle?
Montano1993 [528]
C. 7 cm by 7 cm by 43 cm
5 0
2 years ago
Mathwiz wya?? pic below i need help asap
n200080 [17]

Answer:

Step-by-step explanation:

First, you gotta work out the hypotenuse of ABC, which is AC.

To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.

12.5/5 = 2.5

The scale factor length between the two triangles is 2.5.

You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.

Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB

Pythagoras's theorem = a^2 + b^2 = c^2

a = BC = 12.5

b = AB = we need to work this out

c = AC (the hypotenuse we just worked out) = 32.5

12.5^2 + b^2 = 32.5^2 Let's both simplify and rearrange this at the same time so that we have our b on one side.

b^{2} = 1056.25 - 156.25

b = \sqrt{(1056.25 - 156.25)}

b = \sqrt{900}

b = AB = 30  We've found b or AB, now we can work out the perimeter of ABC.

Perimeter of ABC = AB + BC + AC

= 30 + 12.5 + 32.5

= 75  Here's the perimeter for ABC.

8 0
2 years ago
A basket contains four apples and six peaches. You randomly select one piece of fruit and eat it. Then you randomly select anoth
Sveta_85 [38]

Answer:

Answer as a fraction: 4/15

Answer as a decimal: 0.267

The decimal version is approximate rounded to three decimal places.

Step-by-step explanation:

6 apples, 4 peaches

6+4 = 10 pieces of fruit total

The probability of picking an apple is 6/10 = 3/5

After you pick and eat the apple, there are 10-1 = 9 pieces of fruit left. Also, the probability of picking a peach is 4/9, as there are 4 peaches out of 9 fruit left over.

Multiply out 3/5 and 4/9 to get (3/5)*(4/9) = (3*4)/(5*9) = 12/45 = 4/15

Using a calculator, 4/15 = 0.267 approximately.

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
Read 2 more answers
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