The manager of a store wants to have a sales promotion where she gives prizes to the first several people through the door. She
2 answers:
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Answer:
Image 1
Step-by-step explanation:
To answer this question, we need to know how to use a box plot.
I've attached an image that demonstrates this well and can teach you what each part of the box plot means.
Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.
With this, we can analyze each box plot and determine which one is correct.
<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>
<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.
<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.
<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.
Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.