The area of a triangular prism is 18inches squared. We know the height is 9.5in. What is base a, b, and c?
1 answer:
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Answer:
a) See the code and the figure attached below
b) See the code and the figure attached below
c) We see significant differences on the boxplots. For Catalyst A the variation is less than the variation for Cat B. For both categories we see that we don't have a symmetric distributions. The maximum for Cat A is a little higher than the maximum for Cat B. The median for Cat A is a little higher than Cat B. And the third quartile for Cat A is lower than the third quartile for Cat B.
Step-by-step explanation:
Data given
Catalyst A: 4.4,3.4,2.6,3.8,4.9,4.6,5.2,4.7,4.1,2.6,6.9,0.8,3.6,2.9,2.6,4.0,4.3 .9,4.8,4.5,4.4,3.1,5.7,4.5
Catalyst B: .4,1.1,2.9,5.5,6.4,5.0,5.8,2.5,3.7,3.8,3.1,1.6, 3.5,5.9,6.7,5.2, 6.3, 2.6,4.3, 3.8
Solution to the problem
We are going to use R in order to do the plots required, we put the code and the output its attached to the solution.
Part a
R Code:
> catA<-c(4.4,3.4,2.6,3.8,4.9,4.6,5.2,4.7,4.1,2.6,6.9,0.8,3.6,2.9,2.6,4.0,4.3,0.9,4.8,4.5,4.4,3.1,5.7,4.5 )
> length(catA)
[1] 24
> catB<-c(.4,1.1,2.9,5.5,6.4,5.0,5.8,2.5,3.7,3.8,3.1,1.6,3.5,5.9,6.7,5.2,6.3,2.6,4.3,3.8 )
> length(catB)
[1] 20
> hist(catA)
> hist(catB)
Part b
R code:
> par(mfrow=c(1,2))
> boxplot(catA,main="Boxplot for CatA")
> boxplot(catB,main="Boxplot for CatB")
The result is attached.
Part c
We see significant differences on the boxplots. For Catalyst A the variation is less than the variation for Cat B. For both categories we see that we don't have a symmetric distributions. The maximum for Cat A is a little higher than the maximum for Cat B. The median for Cat A is a little higher than Cat B. And the third quartile for Cat A is lower than the third quartile for Cat B.
Answer:
Answer is 117.86 mm^2
<em>Answer</em><em> </em><em>is given below with explanations</em><em>. </em>
Step-by-step explanation:
<em>HAVE A NICE DAY</em><em>!</em>