Given expression = −50x+100.
Let us understand the structure of the above expression.
Actually above expression is written in slope-intercept form.
y= mx+b, where m is the slope and in other words we call a slope " rate of change", and b is the y-intercept, we take b as fix value.
If we compare −50x+100 by slope-intercept form mx+b, we can see that coefficent of x is -50 there,
Therefore, m=-50.
So, the rate of change of the bank account balance(in dollars per month) = $50/month.
And because it is a negative 50, so we could say the rate of decrease per month is $50.
Work backwards and the answer is :
t= Vp/k
Option C: The solution is 
Explanation:
The given expression is 
We need to solution of the given expression.
The solution of the given expression can be determined by adding the two expressions.
Let us remove the parenthesis.
Thus, we have,

Adding the like terms, we have,

Thus, the solution is 
Hence, Option C is the correct answer.
Answer:
x = -4, 5/2
Step-by-step explanation:
A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.
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A graph is attached. It shows the solutions to be -4 and 5/2.
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When factored, the equation becomes ...
(2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)
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Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...
x = (-b±√(b²-4ac))/(2a)
x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4
x = {-4, 5/2}
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For ax^2 +bx +c = 0, the solutions must satisfy ...
product of solutions is c/a = -20/2 = -10
Only the first and last choices have this product.
sum of solutions is -b/a = -3/2
Only the first choice (-4, 5/2) has this sum.
Answer:
Unusual
Step-by-step explanation:
we know that
The z-score is a measure of how close the given data point is to the mean of the values given with the standard deviation
so
if its z-score is greater than or equal to -2, or less than or equal to 2., then the data value is considered ordinary
if its z-score is less than -2 or greater than 2, then the data value is considered unusual