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Rzqust [24]
3 years ago
14

Two resistors are connected in parallel to a 12 V battery. The potential difference across one of the resistors is 12 v . Calcul

ate the potential difference across the other resistor
Physics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

See the explanation below.

Explanation:

We have to take into account that the potential difference is equal to the voltage, and this is measured between two points as the resistors are connected in parallel to the voltage source, the resistors will have the same voltage.

For ease, we will take the attached image of resistors connected in parallel.

As both resistors at their ends share the A & B connection points, these are at a voltage of 12V

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the exact and absolute age of a rock layer

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An object is placed 10 cm from a convex lens of focal length 20 cm. What is the lateral magnification of the object?.
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Answer:Solution

verified

Verified by Toppr

Given:u=−10cm               f=20cm        (convex lens)

To find: v and image's nature.

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v

1

​

−

u

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2 years ago
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

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