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nikklg [1K]
3 years ago
6

Please help i dont know how to do these so please include explanation

Mathematics
1 answer:
anzhelika [568]3 years ago
4 0
Your answer is 6

Explanation so
L=15
W=4
D=2

15x4=60
60x2=120
Then you use 120divide it by 20 (per hour) and your answer is 6hours
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Frank has four different credit cards, the balances and interest information of which are outlined in the table below. He would
Brums [2.3K]

Answer:

  c.  $467.29

Step-by-step explanation:

The total of balances is $9360. The payment can be computed using the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^-n)

where A is the monthly payment, P is the principal (total balance), r is the annual rate, and n is the number of months.

Filling in your numbers, we have ...

  A = $9360(0.18/12)/(1 -(1 +0.18/12)^-24) ≈ $467.29

Frank's monthly credit card payment will be $467.29.

6 0
4 years ago
Read 2 more answers
HUDSON HAS TO FILL A POT WITH 1 QUART OF WATER. ALL HE HAS IS 1/4 CUP MEASURING CUP. HOW MANY TIMES DOES HE HAVE TO FILL THE 1/4
Marta_Voda [28]
There are 4 cups in a quart.

So if Hudson has only a 1/4 measuring cup, this can be represented by the equation:

4/1/4, solving it we get: 4* 4 (dividing turns a fraction into its reciprocal)

So, 4*4=16

Hudson will have to fill the 1/4 measuring cup 16 times to get a quart.

I hope this helps!
4 0
3 years ago
Read 2 more answers
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

  $H_a:\mu_1 < \mu_2$

  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0
3 years ago
No clue how to do this
andreev551 [17]

B is your awnser! sorry if im wrong my calc shows its without a  - symbol

7 0
3 years ago
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