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Readme [11.4K]
2 years ago
15

The perimeter of a rectangular garden is 43.8 feet. It's length is 12.4 feet. What is its width?​

Mathematics
2 answers:
choli [55]2 years ago
8 0

Answer:

9.5 feet

Step-by-step explanation:

              Multiply the length by two

12.4 times 2 equals 24.8

              Subtract the length from the total perimeter

43.8 minus 24.8 equals 19

           Divide by two to find the final width

19 divided by two equals

ans=9.5

SCORPION-xisa [38]2 years ago
5 0

Answer:

9.5

Step-by-step explanation:

Using the formula

P=2(l+w)

Solving for

w=P

2﹣l=43.8

2﹣12.4≈9.5ft

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2 years ago
An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made
Lemur [1.5K]

Answer:

The dimension of box=2ft\times 2ft\times 1ft

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box=lbh=x^2h

4=x^2h

h=\frac{4}{x^2}

Now, surface area of box,A=x^2+4xh

A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}

\frac{dA}{dx}=2x-\frac{16}{x^2}

\frac{dA}{dx}=0

2x-\frac{16}{x^2}=0

2x=\frac{16}{x^2}

x^3=8

x=2

\frac{d^2A}{dx^2}=2+\frac{32}{x^3}

Substitute x=2

\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0

Hence, the area of box is minimum at x=2

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Hence, the dimension of box=2ft\times 2ft\times 1ft

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Answer:

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