Answer:
= (√3+4√2)/2√6
Step-by-step explanation:
To evaluate cos45*/sec30*+cosec60*
First according to trigonometry identity
sec 30 = 1/cos30
cosec 60 = 1/sin60
Substitute
cos45*/sec30*+cosec60*
= cos45/(1/cos30) + 1/sin60
= cos45coss30 + 1/sin60
= 1/√2 * √3/2 + 1/(√3/2)
= √3/2√2 + 2/√3
= (√9+4√2)/2√6 +
hi
telangana na India na
it looks like its c
sorry if im wrong
x^2y^2.
