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2 years ago

Cos45/sec30+cosec60*

Mathematics

2 answers:

Lera25 [3.4K]2 years ago

7 0

Answer:

= (√3+4√2)/2√6

Step-by-step explanation:

To evaluate cos45*/sec30*+cosec60*

First according to trigonometry identity

sec 30 = 1/cos30

cosec 60 = 1/sin60

Substitute

cos45*/sec30*+cosec60*

= cos45/(1/cos30) + 1/sin60

= cos45coss30 + 1/sin60

= 1/√2 * √3/2 + 1/(√3/2)

= √3/2√2 + 2/√3

= (√9+4√2)/2√6 +

= (√3+4√2)/2√6

Svetradugi [14.3K]2 years ago

3 0

Answer:

telangana na India na

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3 years ago

Find the missing y-coordinate that makes the two triangles congruent. Triangle ABC: A(8,4), B(2,6), C(5, 0) Triangle MNO: M(7,4)

Zolol [24]

Answer:

y = 8

Step-by-step explanation:

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$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

In triangle ABC:

$|AB|=\sqrt{(2-8)^2+(6-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|AC|=\sqrt{(5-8)^2+(0-4)^2}=5\\\\|BC|=\sqrt{(5-2)^2+(0-6)^2 }=\sqrt{45}$

In triangle MNO:

$|MN|=\sqrt{(1-7)^2+(2-4^2)}=\sqrt{40} =2\sqrt{10}\\\\|MO|=\sqrt{(4-7)^2+(y-4)^2}\\\\|NO|=\sqrt{(4-1)^2+(y-2)^2 }$

Since triangle ABC and triangle MNO are congruent, hence:

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$|AC|=|MO|=5\\\\\sqrt{(4-7)^2+(y-4)^2}=5\\\\(4-7)^2+(y-4)^2=25\\\\9 +(y-4)^2=25\\\\(y-4)^2=16\\\\square\ root\ of\ both\ sides:\\\\y-4=4\\\\y=4+4\\\\y=8$

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3 years ago

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3 years ago

Read 2 more answers

If the circumference of a circle is 36π, what is the length of a radius of the circle?

m_a_m_a [10]

Answer:

The answer is 6 (A)

Step-by-step explanation:

The exact answer is 5.73, but I think in the question they are rounding to the nearest whole number, so the rounded answer is 6.

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2 years ago

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Irina-Kira [14]

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3 years ago

Cos45*/sec30*+cosec60*​

Cos45/sec30+cosec60*