Answer:
0.46
Step-by-step explanation:
Answer:
(a+b)1/3+a^2
Step-by-step explanation:
Hope it helps!
Given:
The ratio of 45-45-90 triangle is
.
The hypotenuse of the given isosceles right triangle is
.
To find:
The lengths of the other two sides of the given isosceles right triangle.
Solution:
Let
be the lengths of the other two sides of the given isosceles right triangle.
From the given information if is clear that he ratio of equal side and hypotenuse is
. So,




Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.
Answer: Option B, Option C, Option E
Step-by-step explanation:
The options written correctly, are:

For this exercise you need to use the following Inverse Trigonometric Functions:

When you have a Right triangle (a triangle that has an angle that measures 90 degrees) and you know that lenght of two sides, you can use the Inverse Trigonometric Functions to find the measure of an angle
:

Therefore, the conclusion is that the angles "x" and "y" can be found with these equations:

Answer
The answer is It's 9 = Answer B