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3 years ago

What is currently the most supported theory about the future of the universe

Physics

2 answers:

mamaluj [8]3 years ago

8 0

the answer is B! it would continue to expand.....just took the test XD

wlad13 [49]3 years ago

4 0

Answer:

B.) the universe may continue to expand

Explanation:

The steady state theory which states that the universe was, is and will be the same, has been discredited by two physicists who found the leftover energy from the big bang.

If you are listening to FM radio, you might have heard some static noise while changing stations, that noise is from the leftover energy from the big bang. This energy is called the dark energy.

The dark energy tries to rip everything apart while gravity tries to hold everything together.

It was observed that the dark energy is stronger than gravity.

The distance between the galaxies is increasing. This proves that the dark energy successfully defeated the gravity and expanted two massive objects in the universe.

Because of this dark energy the universe will continue to expand.

Note: Dark energy is also increasing the distance between protons in atomic nucleus in every atom in our body too. Chilly right?

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Pepe and Alfredo are resting on an offshore raft after a swim. They estimate that 3.0 m separates a trough and an adjacent crest

Agata [3.3K]

Answer:

The velocity ( $v$ ) of the wave is 3.08 $ms^{-1}$ .

Explanation:

According to the figure, the distance ( $\large{L}$ ) between a trough and its adjacent crest is $\large{L = 3 m}$ . Also the wavelength ( $\large{\lambda}$ ) of the wave is $\large{\lambda = 2L}$ . Pepe and Alfredo count 11 crests to pass the raft in $\large{t}$ = 21.5 s.

So, the time period ( $\large{T}$ ) of oscillation of the wave is

$\large{T} = \dfrac{t}{11} = \dfrac{21.5}{11} = 1.95s$

So, the velocity ( $\large{V}$ ) of the wave is

$\large{V = \dfrac{\lambda}{T} = \dfrac{2 \times L}{T} = \dfrac{2 \times 3}{1.95}= 3.08 ms^{-1}}$

4 0

3 years ago

The voltage in the lines that carry electric power to homes is typically 2000 V. What is the required ratio of the loops in the

mariarad [96]

Answer:

yurrrrr 221n54

Explanation:

yurrrrrrrrrrrrrrrrrrrrrr

6 0

3 years ago

Read 2 more answers

If a pulley with six supporting ropes is used to lift a 1200 lb piano, what input force is needed?

Lisa [10]

The correct answer is d) 200 lbs.

Hope that I was of help.

3 0

3 years ago

Read 2 more answers

A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou

Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

$\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m$

$\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s$

State 2 : constant speed

$\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m$

State 3 : deceleration

$\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)$

$\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m$

Total distance : state 1+ state 2+state 3

$\tt 200 + 36000 + 300=36500~m$

the average velocity = total distance : total time

$\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s$

4 0

3 years ago

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,

lbvjy [14]

Answer:

The value is $T_c = 12 .1 ^oC$

Explanation:

From the question we are told that

The mass of the ice cube is $m_i = 7.50 *10^{-3} \ kg$

The temperature of the ice cube is $T_i = 0^o C$

The mass of the copper cube is $m_c = 0.540 \ kg$

The final temperature of both substance is $T_f = 0^oC$

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

$Q = m_c * c_c * [T_c - T_f ]$

The specific heat of copper is $c_c = 385J/kg \cdot ^oC$

Generally the heat gained by the ice cube is mathematically represented as

$Q_1 = m_i * L$

Here L is the latent heat of fusion of the ice with value $L = 3.34 * 10^{5} J/kg$

$Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}$

=> $Q_1 = 2505 \ J$

$2505 = 0.540 * 385 * [T_c - 0 ]$

=> $T_c = 12 .1 ^oC$

4 0

3 years ago