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mote1985 [20]
3 years ago
15

What is currently the most supported theory about the future of the universe

Physics
2 answers:
mamaluj [8]3 years ago
8 0

the answer is B! it would continue to expand.....just took the test XD

wlad13 [49]3 years ago
4 0

Answer:

B.) the universe may continue to expand

Explanation:

The steady state theory which states that the universe was, is and will be the same, has been discredited by two physicists who found the leftover energy from the big bang.

If you are listening to FM radio, you might have heard some static noise while changing stations, that noise is from the leftover energy from the big bang. This energy is called the dark energy.

The dark energy tries to rip everything apart while gravity tries to hold everything together.

It was observed that the dark energy is stronger than gravity.

The distance between the galaxies is increasing. This proves that the dark energy successfully defeated the gravity and expanted two massive objects in the universe.

Because of this dark energy the universe will continue to expand.

Note: Dark energy is also increasing the distance between protons in atomic nucleus in every atom in our body too. Chilly right?

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How does friction make it possible for you to walk across the floor?
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Hope those helps :)

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One hazard of space travel is the debris left by previous missions. There are several thousand objects orbiting Earth that are l
MariettaO [177]

Answer:

F = 6666.7 N

Explanation:

Given that,

Mass of a chip, m = 0.1 mg

Initial speed, u = 0

Final speed,v=4\times 10^{3}\ m/s

Time of collision,t=6\times 10^{-8}\ s

We know that,

Force, F = ma

Put all the values,

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.1\times 10^{-6}\times (4\times 10^3-0)}{6\times 10^{-8}}\\\\F=6666.7\ N

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3 years ago
A rifle is aimed horizontally at a target 49 m away. the bullet hits the target 2.3 cm below the aim point. part a what was the
Nezavi [6.7K]

We use the equation of motion for vertical component,

s_{y} = u_{y} t+\frac{1}{2} gt^2.

Here, s_{y}   is displacement of bullet, u_{y}  is vertical initial velocity of bullet which is equal to zero because bullet was fired horizontally, and t is time of flight.

Therefore,

s_{y} =\frac{1}{2}gt^2

Given, s_{y} =2.3 \ cm = 2.3 \times 10^{-2} \ m

Substituting the values, we get time of flight

2.3 \times 10^{-2} \ m = \frac{1}{2} \times 9.8 \ m/s^2 \times t^2 \\\\ t =\sqrt{46.94 \times 10^{-4} \ s } = 0.069 \ s

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