The answer is do not break, the key avoiding skids is to always smoothly apply your brakes and accelerator and to turn slowly and smoothly. Reducing of the speed before oncoming turns and once driving in possibly hazardous circumstances such as wet, icy or snow covered roadways or on roadways with loose gravel.
A quantity that has magnitude and direction
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
Answer:

Explanation:
Given data:
mass of block is 
radius of block = 0.061 m
moment of inertia is 
D is distance covered by block = 0.65 m
speed of block is 1.705 m/s
From conservation of momentum we have

![0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times 0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l](https://tex.z-dn.net/?f=0.84%20%5Ctimes%209.81%20%5Ctimes%200.65%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%200.84%20%5Ctimes%201.705%5E2%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%206.2%20%5Ctimes%2010%5E%7B-3%7D%20%5B%5Cfrac%7B1.705%7D%7B0.061%7D%5D%5E2%20%2B%20E_l)
solving for energy loss

I believe the answer would be mass. Low mass stars and medium mass stars often become white dwarfs when they die while high mass stars explode in violent explosions called supernovas and usually leave behind a black hole or a neutron star.