Question

Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and the density of the gas is 0.710 g/cm3, how many kilograms of fuel are contained in one canister? Express the mass in kilograms to three significant figures.

Answer 1

Answer: One canister contains 1.03 Kg of fuel,

Explanation:

The density is defined as the relation between the mass and the volume $p=\frac{m}{v}$

First of all you need to have the same units for volume and density, so:

For the volume,

$1.45 L * \frac{1.10*10^{-3}m^{3} }{1 L} = 1.45 *10^{-3} m^{3}$

For the density,

$p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3} }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }$

From the density equation we have $m=p*v$, so:

$710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg$