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kolezko [41]
3 years ago
12

Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two

graphs are equivalent provided that they have the same number of edges. How many equivalence classes are there?
Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

7

Step-by-step explanation:

Let S be the set of all graphs having vertex set  \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

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Answer:

Where is the question?

Step-by-step explanation:

3 0
2 years ago
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Present Value Hoew much shuold be deposited in an account paying 7.2% interest compounded monthly in order to have a balance of
jonny [76]

Answer:$6451.6 should be deposited.

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 7.2%. So

r = 7.2/100 = 0.072

It was compounded for 3 years. So

t = 3

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. A is given as $8000 Therefore,

8000 = P (1+0.072/12)^12×3

8000 = P(1+0.006)^36

8000 = P(1.006)^36

P = 8000/1.24

P = $6451.6

6 0
3 years ago
A couch, a love seat, and a chair cost $1565. The couch costs twice as much as the chair, and the love seat costs $400 more than
Brilliant_brown [7]
The answer to the question is 1565÷400=3.9125
6 0
3 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
Marty ate 1/4 of his pizza and Luis ate 1/3 of his pizza. Marty ate more pizza than Luis. Is that possible?
Nataly_w [17]
Of course.

You can only say for sure that 1/4 of a whole thing is less than 1/3 of a whole thing
if the whole things are equal size.

If Marty's pizza was 1/3 bigger than Luis' pizza, then they both ate the same amount.
If Marty's was MORE than 1/3 bigger than Luis', then Marty ate more pizza.
8 0
3 years ago
Read 2 more answers
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