Answer:
0.5849Weber
Explanation:
The formula for calculating the magnetic flus is expressed as:

Given
The magnitude of the magnetic field B = 3.35T
Area of the loop = πr² = 3.14(0.24)² = 0.180864m²
angle of the wire loop θ = 15.1°
Substitute the given values into the formula:

Hence the magnetic flux Φ through the loop is 0.5849Weber
Answer:
A. 12,240.
Explanation:
1,530 times 8.0 = 12,240.
hope this helped :)
Answer:
It will be A. So since its 2 times more the kinetic energy. But then you have to square it 2^2 = 4
Answer:
Explanation:
The equivalent resistance for three resistors connected in parallel is given as
(1/R)=(1/R₁)+(1/R₂)+(1/R₃)
now we.need to.insert the value of 3 resistances but only 2 are given in the question.
Answer:
it depends on the weight's ratio
(sorry)