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3 years ago

The atomic mass of an element whose atoms consist of seven protons, eight neutrons, and seven electrons is _____?

2 answers:

6 0

The atomic mass is C. 15

Atomic mass = P + N = 7+8 = 15

The atomic mass of an element is defined as the sum of the protons and neutrons. On the other hand, the atomic number of a neutral element is equivalent to the number of protons or electrons. This is because a neutral element should have equal number of protons and electrons.

MrRissso [65]3 years ago

3 0

Answer:

Explanation:

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AfilCa [17]

From information given, there are two forces in action, the vertical and the horizontal. We first need to calculate separately work done by these two forces, then determine the efficiency. Work = Force × distance work(a) → 600N × 2m = 1,200 Nm work(b) → 300N × 5m = 1,500 Nm Efficiency = work(a) / work (b) × 100 Efficiency = 1200 / 1500 × 100 Efficiency = 0.8 × 100 Efficiency = 80% Therefore the efficiency of the ramp is 80%

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3 years ago

A) a 50 kg gymnast jumps from the balance beam with a speed of 1.7m/s. she lands upright on the ground 124cm below. At what spee

ivolga24 [154]

PART a)

By energy conservation we can say

$PE_i + KE_i = PE_f + KE_f$

$mgh_1 + \frac{1}{2}mv_i^2 = mgh_2 + \frac{1}{2}mv_f^2$

divide whole equation by mass "m" and plug in all given data

$9.8(1.24) + \frac{1]{2}(1.7)^2 = 9.8(0) + \frac{1}{2}(v)^2$

$v_f = 5.21 m/s$

so gymnast will reach the floor with speed 5.21 m/s

PART b)

Now the gymnast bend her knees by 0.1 m and comes to rest

so here we will have

$v_f^2 - v_i^2 = 2 a d$

$0 - 5.21^2 = 2(a)(0.1)$

$a = 135.97 m/s^2$

now the force on the gymnast will be

$F = ma$

$F = 50 \times 135.97 = 6798.5 N$

so during landing the force will be 6798.5 N

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3 years ago

Holding health care personal to lesser standards of care in emergencies is call the what statue?

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Hello there,

Holding health care personal to lesser standards of care in emergencies is call the what statue?

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2 years ago

47. Calculate the final steady temperature obtained when

Rashid [163]

Answer:

the final steady temperature of the mixture is 46.67 ⁰C

Explanation:

Given;

mass of first water,m₁ = 6 g = 0.006 kg

initial temperature, t₁ = 50 ⁰C

mass of the second water, m₂ = 3.0 g = 0.003 kg

initial temperature of the second water, t₂ = 40 ⁰C

specific heat capacity of water, C = 4,200 J/kg.K

Let the final temperature of the mixture = T

Based on Law of conservation of energy, the temperature of the final mixture is calculated as follows;

m₁c(t₁ - T) = m₂c(T - t₂)

0.006 x 4200 x (50 - T) = 0.003 x 4200 x (T - 40)

1,260 - 25.2T = 12.6T - 504

1,260 + 504 = 12.6T + 25.2T

1764 = 37.8T

T = 1764/37.8

T = 46.67 ⁰C

Therefore, the final steady temperature of the mixture is 46.67 ⁰C

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2 years ago

Why does increasing the number trials increase confidence in the results of the experiment?

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If you increase the number of trials in an experiment it will make the test more valid and legitimate.As you take the same test/experiment once or twice you could see if your results are similar to each other.

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3 years ago

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