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Alex73 [517]
3 years ago
6

Name three possible end stages of a star​

Physics
1 answer:
Ahat [919]3 years ago
4 0
Black hole, neutron Star, or super nova
You might be interested in
Sam receives the kicked football on the 3 yd line and runs straight ahead toward the goal line before cutting to the right at th
Pie

Answer:

Distance: 21 yd, displacement: 15 yd, gain in the play: 12 yd

Explanation:

The distance travelled by Sam is just the sum of the length of each part of Sam's motion, regardless of the direction. Initially, Sam run from the 3 yd line to the 15 yd line, so (15-3)=12 yd. Then, he run also 9 yd to the right. Therefore, the total distance is

d = 12 + 9 = 21 yd

The displacement instead is a vector connecting the starting point with the final point of the motion. Sam run first 12 yd straight ahead and then 9 yd to the right; these two motions are perpendicular to each other, so we can find the displacement simply by using Pythagorean's theorem:

d=\sqrt{12^2+9^2}=15 yd

Finally, the yards gained by Sam in the play are simply given by the distance covered along the forward-backward direction only. Since Sam only run from the 3 yd line to the 15 yd line along this direction, then the gain in this play was

d = 15 - 3 = 12 yd

7 0
3 years ago
What is the magnitude of the torque about his shoulder due to the weight of the ball and his arm if he holds his arm straight ou
Lubov Fominskaja [6]

Answer:

The torque about his shoulder is 34.3Nm.

The solution approach assumes that the weight of the boy's arm acts at the center of the boy's arm length 35cm from the shoulder.

Explanation:

The solution to the problem can be found in the attachment below.

6 0
3 years ago
What is the wavelength of a wave that has a speed of 350 meters/second and a frequency of 140 hertz?In meters
Leto [7]
Apply:
wavelength = speed/frequency
= 350 m/s : 140 Hz = 2.5 m.
3 0
3 years ago
Read 2 more answers
Find the voltage across the 15 Q resistor.<br> [?] V<br><br> No links please
Margaret [11]

Answer:

Explanation:

same idea as before Liam,  first, find the parallel resistance in 35 || 20

(35*20)  / (35+20)  = 700 / 55  = 12.727272 ohms

now add the  12.727272 + 15 = 27.727272 ohms total resistance

V = IR

10 = I *    27.727272

10 / 27.727272 = I

0.360655 = I

V = IR  (again, but across the 15 ohm resistor)

V =     0.360655 * 15      

V = 5.4098                

4 0
2 years ago
How much heat is required to convert 2.55g of water at 28 degrees c to steam?
pantera1 [17]
There are two different processes here:
1) we must add heat in order to bring the temperature of the water from 28^{\circ}C to 100^{\circ}C (the temperature at which the water evaporates)
2) other heat must be added to make the water evaporates

1) The heat needed for process 1) is
Q_1=m C_s \Delta T
where 
m=2.55 g is the water mass
C_s = 4.18 g/J^{\circ}C is the water specific heat
\Delta T=100^{\circ}C-28^{\circ}C=72^{\circ}C is the variation of temperature of the water
If we plug the numbers into the equation, we find
Q_1 = (2.55 g)(4.18 J/g^{\circ}C)(72^{\circ}C)=767.4 J

2) The heat needed for process 2) is
Q=m L_e
where 
m=2.55 g is the water mass
L_e = 2264.7 J/g is the latent heat of evaporation of water
If we plug the numbers into the equation, we find
Q_2=(2.55 g)(2264.7 J/g)=5775.0 J

So, the total heat needed for the whole process is
Q=Q_1+Q_2=767.4 J+5775.0 J=6542.4 J
4 0
3 years ago
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