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zimovet [89]
3 years ago
15

The Milky Way is our Galax. Where are we located in Milky Way?​

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Earth is located in one of the spiral arms of the Milky Way (called the Orion Arm) which lies about two-thirds of the way out from the center of the Galaxy.

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the kinetic energy of an object with mass m moving with a velocity of 5 m/s is 25 j what will be its kinetic energy when its vel
Dmitriy789 [7]

Answer:

100 J, 225 J

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is the velocity of the object

In this problem, the initial kinetic energy of the object is

K = 25 J

Then, the velocity is doubled, which means

v' = 2v

Therefore, the new kinetic energy will be

K'=\frac{1}{2}m(2v)^2 = 4(\frac{1}{2}mv^2)=4K

Therefore, the kinetic energy has quadrupled:

K' = 4(25)=100 J

Later, the velocity is tripled, which means

v'' = 3v

Therefore, the new kinetic energy will be

K''=\frac{1}{2}m(3v)^2 = 9(\frac{1}{2}mv^2)=9K

Therefore, the kinetic energy has increased by a factor of 9:

K' = 9(25)=225 J

4 0
3 years ago
When attempting to determine the coefficient of kinetic friction, why is it necessary to move the block with constant velocity
Readme [11.4K]

Answer:

Explanation:

In order to measure the coefficient of friction , we apply external force to move the body . When external force comes in motion , we adjust the external force so that it moves with zero acceleration or uniform velocity . In this case external force becomes equal to kinetic frictional force and then net force becomes zero because

net force = mass x acceleration = m x 0 = 0

Now frictional force = μ mg where μ is coefficient of kinetic friction

so F = μ mg where F is external force applied

μ = F / mg

Hence , to make external force equal to frictional force , it is necessary to make acceleration of body zero .

4 0
3 years ago
During a tennis serve, a racket is given an angular acceleration of magnitude 150 rad/s^2. At the top of the serve, the racket h
QveST [7]

Answer:

270 m/s²

Explanation:

Given:

α = 150 rad/s²

ω = 12.0 rad/s

r = 1.30 m

Find:

a

The acceleration will have two components: a radial component and a tangential component.

The tangential component is:

at = αr

at = (150 rad/s²)(1.30 m)

at = 195 m/s²

The radial component is:

ar = v² / r

ar = ω² r

ar = (12.0 rad/s)² (1.30 m)

ar = 187.2 m/s²

So the magnitude of the total acceleration is:

a² = at² + ar²

a² = (195 m/s²)² + (187.2 m/s²)²

a = 270 m/s²

3 0
3 years ago
does anyone know how to do this? the scenario is ""dominique reads that race cars have wide tires because the increased area of
Usimov [2.4K]

Answer:

Stupid

Explanation:

Because there is never a answer when we are trying to find one

7 0
3 years ago
A satellite with a mass of 110 kg and a kinetic energy of 3.0 ´ 109 J must be moving at a speed of
djverab [1.8K]

Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.

Explanation: To find the answer we need to know about the kinetic energy of a body.

<h3>How to solve the problem the equation of kinetic energy?</h3>
  • We have the expression for kinetic energy of a body as,

                                   KE=\frac{1}{2}mv^2

  • Given that,

                                   m=110kg\\KE=3.08*10^9J\\

  • We have to find the speed of the satellite,

                               v=\sqrt{\frac{2KE}{m} } =\sqrt{\frac{2*3.08*10^9}{110} } =7.483*10^3 m/s

Thus, we can conclude that, the velocity of the satellite will be 7438m/s.

Learn more about Kinetic energy here:

brainly.com/question/28105739

#SPJ4

8 0
2 years ago
Read 2 more answers
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