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3 years ago

Please help timed question (question included in photo). I'll mark as brainiest!

Mathematics

2 answers:

Shtirlitz [24]3 years ago

8 0

Answer:

Step-by-step explanation:

This is a right triangle trig problem. Picture a right triangle. The height of the triangle is the height of the lighthouse, your distance from the base of the lighthouse is what we are solving for, and the reference angle is 2 degrees, which is the angle of inclination from where you stand to the top of this lighthouse. We have the reference angle, the side opposite the reference angle, and we are looking for the side adjacent to the reference angle. This is the tangent ratio: the side opposite the reference angle over the side adjacent to the reference angle. We know the measure of the reference angle and we know the value of the side opposite the reference angle. Filling in:

$tan(2)=\frac{200}{x}$ and

$x=\frac{200}{tan(2)}$ so

x = 5727.25 feet, the third choice down

Lostsunrise [7]3 years ago

3 0

Answer:

$tan2=200/x$ $x=200/tan2$

$x=5,727.25$

hope it helps..

have a great day!!

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A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

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Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

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The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

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Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

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Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

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$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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