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snow_tiger [21]
3 years ago
14

Please , can someone answer thisss TmT

Mathematics
2 answers:
Tems11 [23]3 years ago
5 0

Answer:

7

Step-by-step explanation:

We have that x1=−1, y1=5, x2=3, y2=7.

Plug the given values into the formula for a slope: m=7−(5)3−(−1)=12.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b=5−(12)(−1)=112

Finally, the equation of the line can be written in the form y=b+mx:

y=112+x2

ANSWER

IgorC [24]3 years ago
4 0

Answer:

-6

Step-by-step explanation:

can u mark me as a brainliest plz?

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slope = 2

Step-by-step explanation:

Pick two points to find the slope. (1, 2) and (3, 3)

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2.5 hours

Step-by-step explanation:

it takes him 2.5 hours

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3 years ago
Read 2 more answers
Can someone help me out please, thank you.
Nutka1998 [239]

Here are a few rules about exponents you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  3. Powering a power to a power: (x^m)^n=x^{m*n}
  4. Converting a negative exponent into a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

Firstly, multiply the y bases: \frac{z^5}{(-y^{-4}y^{-1}x^3)^{-3}}=\frac{z^5}{(-y^{-4+-1}x^3)^{-3}}=\frac{z^5}{(-y^{-5}x^3)^{-3}}

Next, solve the power: \frac{z^5}{(-y^{-5}x^3)^{-3}}=\frac{z^5}{-y^{-5*-3}x^{3*-3}}=\frac{z^5}{-y^{15}x^{-9}}

Finally, convert the negative exponent into a positive one and <u>your final answer will be: -\frac{z^5x^9}{y^{15}}</u>

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