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dexar [7]
3 years ago
13

You construct a simple electrical current to boil water for tea. A battery generates positive and negative charges. A wire conne

cts the battery to a hot plate. When you close the circuit, the hot plate turns on and heats the tea kettle. Which object in this circuit is the load?
Computers and Technology
1 answer:
jeka943 years ago
8 0

Answer:

The hot plate

Explanation:

An electrical component that consumes or takes up the current in the circuit is known as the load.

In this circuit, the hot plate takes up the current produced when the circuit is closed. The current it take up is used to heat up the tea kettle.

Hence, we can see from the foregoing that the hot plate is the load in this circuit.

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C. Source-Encoding-Message channel-Noise-Receiver-Feedback

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Debug the code in the starter file so if functions as intended and does not cause any errors. This program is intended to take t
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Debugging a code involves finding and fixing the errors in a code.

The errors in the code are as follows:

  • <em>Class name</em>
  • <em>Print statements</em>
  • <em>Variable declarations</em>
  • <em>Input statements</em>
  • <em>If condition</em>

<em><u /></em>

<u />

<u>The class name </u>

The class name of the program is <em>U3_L5_Activity Two</em>

A class name cannot <em>contain space</em>; instead you make use of an <em>underscore.</em>

So, the correct class name is: <em>U3_L5_Activity_Two or U3_L5_ActivityTwo</em>

<u>The print statement</u>

Java differentiates lower and upper case letters.

The print statements in the program begin with a <em>small letter s</em>. This is wrong

So, the correct statements are:

  • <em>System.out.println("Enter two numbers");</em>
  • <em>System.out.println(b + " is a multiple of " + a);}</em>
  • <em>System.out.println(b + " is not a multiple of " + a);</em>

<u />

<u>The declaration and the input statements</u>

Variables a and b were declared wrongly, and the input statements are also wrong.

The correct statements are:

  • <em>int a = scan.nextInt(); </em>
  • <em>int b = scan.nextInt(); </em>

<em />

<u>The condition</u>

The if condition is not properly formatted.

The correct statement is: <em>iif(b%a == 0)</em>

Hence, the correct code is:

<em>import java.util.Scanner; </em>

<em>public class Main{ </em>

<em>public static void main(String[] args) { </em>

<em>    Scanner scan = new Scanner(System.in); </em>

<em>    System.out.println("Enter two numbers"); </em>

<em>    int a = scan.nextInt(); </em>

<em>    int b = scan.nextInt(); </em>

<em>    if(b%a == 0){ </em>

<em>        System.out.println(b + " is a multiple of " + a);} </em>

<em>    else{ </em>

<em>        System.out.println(b + " is not a multiple of " + a); </em>

<em>    } </em>

<em>} </em>

<em>}</em>

<em />

Read more about debugging at:

brainly.com/question/23527739

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3 years ago
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