As x approaches 5
hmm, we can divide the (x-5) from top and bottom to get x-5
if we input 5 for x we get
5-5=0
it approaches 0 as x approaches 5
We have such equation
1.25x=0.75x+50 /-0.75x (subtract 0.75 both sides)
1.25x-0.75x=0.75x-0.75x+50
0.5x=50 /*2 (multiply both sides times 2)
0.5x*2=50*2
x=100 - its the answer
Do you have any options of the equivalent expressions or is it just a plan question that you just asked?
If X > 0 then X must be a positive number. If Y < 0 then Y must be negative. So the quadrant that contains Positive X values and negative Y values will contain the point that you are looking for. This would be the fourth quadrant.