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vodomira [7]
3 years ago
14

The volume of a rectangular prism is (x^3 – 3x^2 + 5x – 3), and the area of its base is (x^2 – 2). If the volume of a rectangula

r prism is the product of its base area and height, what is the height of the prism?
Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

The height of the prism is equal to h=(x^{3}-3x^{2}+5x-3)/(x^{2}-2)

Step-by-step explanation:

we know that

The volume of a rectangular prism  is equal to

V=Bh

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

V=x^{3}-3x^{2}+5x-3

B=x^{2}-2

substitute in the formula and solve for h

x^{3}-3x^{2}+5x-3=(x^{2}-2)h

h=(x^{3}-3x^{2}+5x-3)/(x^{2}-2)

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Doss [256]

Answer:

20 degree

Step-by-step explanation:

x + x + 70 = 110 degree (sum of two opposite interior angle equal to the exterior angle formed)

2x = 110 - 70

x = 40/2

x = 20 degree

3 0
3 years ago
What are the coefficients in the polynomial 4x2 + 3x-3?
Ksenya-84 [330]

                   - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

        What are the coefficients in the polynomial 4x²+3x-3?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond

<u>Coefficient:-</u>  A number before a variable

<u>Coefficients in this polynomial:-</u>

4 (the number before x²) and 3 (the number before x)

<h3 />

So we conclude that the right option is:-

\bigcirc\!\!\!\!\!\large\checkmark 4, 3 (Option B)

<h3>Good luck.</h3>

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4 0
2 years ago
((5^(3))^(5))/(5^(7))
Norma-Jean [14]

Answer:

48

Step-by-step explanation:

equals 48 trust me ive had that question

6 0
3 years ago
Read 2 more answers
2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
ddd [48]
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
5 0
3 years ago
F(x)=tan(x)
AleksAgata [21]
<span>Tan(x) = sin(x) / cos(x). Therefore, tan(x) pi/2 = 1/0, which doesn't exist. Imagine that, instead of 0, it's a number incredibly close to 0. The smaller the number in the denominator, the bigger the outcome. Therefore, we can think of 1/0 as infinity, or approaching infinity as one gets closer to 1/0. This is the same result approaching from the negative side, only it's negative infinity. If x=0, it's 0/1 instead (sin 0=0, cos 0=1). Anything divided by 1 is itself, so as x approaches 0, so does f(x).</span>
7 0
3 years ago
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