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3 years ago

Match each statement with one of these terms.

Chemistry

1 answer:

skelet666 [1.2K]3 years ago

8 0

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time

The process of extracting a component that is adsorbed to a given material by use of an appropriate solvent system. -- Elution

Measure of chromatographic column efficiency. The greater its value, the more efficient the column. -- Theoretical plate number

Gas, liquid, or supercritical fluid used to transport the sample in chromatographic separations. -- Mobile phase

Immiscible and immobile, it is packed within a column or coated on a solid surface. -- Stationary phase

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Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V

malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

4 0

3 years ago

A solution contains an unknown amount of dissolved magnesium. Addition of

Scrat [10]

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Mg²⁺: 1 mole
Na₂CO₃: 1 mole
MgCO₃: 1 mole
Na⁺: 2 moles

The molar mass of the compounds is:

Mg²⁺: 24.3 g/mole
Na₂CO₃: 106 g/mole
MgCO₃: 84.3 g/mole
Na⁺: 23 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Mg²⁺: 1 mole ×24.3 g/mole= 24.3 grams
Na₂CO₃: 1 mole ×106 g/mole= 106 grams
MgCO₃: 1 mole ×84.3 g/mole=84.3 grams
Na⁺: 2 moles ×23 g/mole= 46 grams

<h3>Mass of magnesium dissolved</h3>

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

$mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}$

<u><em>mass of magnesium= 2.13 grams</em></u>

Finally, 2.13 grams of magnesium was dissolved in the solution.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

4 0

3 years ago

How many moles of neon occupy a volume of 14.3 l at stp? how many moles of neon occupy a volume of 14.3 l at stp? 1.57 moles 0.6

andriy [413]

The number of neon moles that occupy a volume of 14.3 l at STP is calculated as follows

At STP 1 mole = 22.4 liters

what about 14.3 liters

by cross multiplication
= (1 mole x 14.3 l)/22.4 l =0.638 moles of neon

5 0

3 years ago

A scale model of the solar system

Ket [755]

There you go BRAINLIEST would be appreciated

3 0

3 years ago

The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:

alisha [4.7K]

Answer:

b. potassium.

Explanation:

Potassium-sparing diuretics and salt substitutes are diuretics that eliminate salt and water but save potassium. They act by inhibiting the conducting sodium channels in the collecting tubule, such as amiloride and triamterene, or by blocking aldosterone, such as spironolactone.

Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

4 0

3 years ago