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ELEN [110]
2 years ago
13

Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V

A) Write the equation for the half-reaction occurring at the cathode.B) Write the equation for the half-reaction occurring at th anodeC) Write the overall equation for the cell reation.D) what is the standard cell potential EoCell, for the Cell?
Chemistry
1 answer:
malfutka [58]2 years ago
4 0

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

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Answer:

The correct option is;

Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C

Explanation:

The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics

1) The constant terms for the experiment should be defined, which in this case are

a) The volume of the water which is 60 ml in both subjects of the experiment

2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects

3)The environmental limits of the experiment, which is the water and the food coloring used

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Given the reaction: cu(s) + 4hno3(aq) → cu(no3)2(aq) + 2no3(g) + 2h2o(l )as the reaction occurs, what happens to copper?
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From the reaction between Cu and HNO₃, the formed gas is NO₂ instead of NO₃. Hence the correct balanced equation would be,
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Here, Cu goes to </span>Cu(NO₃)₂ by changing its oxidation number from 0 to +2 while NO₃⁻ goes to NO₂ by reducing its oxidation state from +5 to +4 . Hence Cu is oxidized by HNO₃ in the reaction.
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7 0
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3 years ago
In the single displacement reaction of HCl and magnesium, how many grams of magnesium chloride would be produced if 1.05g of mag
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Answer:

4.16g of MgCl2

Explanation:

First, let us generate a balanced equation for the reaction:

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