If iodine has a 13.3 hour half life, 3.12 mg of the original sample will still be present after 39.9 hours.
<h3>what is The meaning of half-life?</h3>
The reaction rate must decrease to half its initial value before the process has reached its half life. The split of that first order chemical reaction is a quantity related to the rate constant of the reaction.
Briefing:
Given, the iodine half-life is 13.3 hours. As a result, half-life t1/2 Equals ln 2/ K
k = 0.693 .... t1/2
≈ 0.693 /13.3 hours
= 5.21 *10-2
The rate law sets the flow timetime is set by the rate law, which varies for each emotion. When only one reactant's quantity influences the speed of chemical reaction, this is referred to as a first-order contact. Because of this, it is occasionally referred to as unimolecular process. The rate is as follows for this type of reaction: k= 1/t ln [A]0 / [A] is the rate constant for the first order reaction. 5.21 * 10-2 hours are in 39.9 hours.
By including all the numbers in the initial order reaction's rate constant equation, we obtain [A].
t = 3.12mg
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In the Terrestrial ecosystem, examples might include the following such as tempature, light and water. In the Ocean Ecosystem, abiotic factors would include salinity and ocean currents
Explanation:
i think that will help. I only tried so it might not be correct , so let me Know if it's correct
Photosynthesis supports the Law of Conservation of Matter/Mass and Energy because it isn't destroying matter or energy, the process of photosynthesis is simply converting matter into a usable form of energy which, in this case, is ATP.
Answer:
The answer to your question is SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Explanation:
Reaction
SO₂ + H₂ ⇒ H₂S + H₂O
Reactants Elements Products
1 Sulfur 1
2 Hydrogen 4
2 Oxygen 1
This reaction is unbalanced so we need to balance it.
SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Reactants Elements Products
1 Sulfur 1
6 Hydrogen 6
2 Oxygen 2
Now, the reaction is balanced