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kramer
3 years ago
7

Can someone please help me with this I’m struggling

Mathematics
2 answers:
iragen [17]3 years ago
8 0

Answer:

Equation:  70=(x+3)x

x = -10 or x = 7

x = 7 (width can't be negative)

x + 3 = 10

Step-by-step explanation:

Represent the width of the rectangle by  x.  "The length of a rectangle EXCEEDS the width by 3" means the length is 3 LONGER than the width, so the length is represented by the expression  x + 3.

Area = (length)(width)

70 = (x + 3)x

Multiply out the right side.

70=x^2+3x\\x^2+3x-70=0

Factor the left side.

(x+10)(x-7)=0

Each binomial could equal 0, so

x+10=0 \text{ or }x-7=0\\x=-10\text{ or }x=7

The negative solution does not make sense as the width of a rectangle.

x = 7, making the length, x + 3 = 10

Romashka-Z-Leto [24]3 years ago
7 0

Answer:

Pls mark this as brainiest

Step-by-step explanation:

Area of the rectangle = length x breadth

consider 'x' to be width

therefore length = x+3

area = (x+3)*x

Area = 70 square

x = 7

x+3 = 7+3

      = 10

verification

7 x 10

= 70

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S = 4LW + 2WH; S = 168, L = 8, W = 4<br><br> H=
IRISSAK [1]

Answer:

umm check your math book in page 445

Step-by-step explanation:

5 0
3 years ago
Can anybody tell me how to solve this
Lyrx [107]
The answer to your question is:  Yes, someone undoubtedly can.

Although you haven't asked to be told or shown how to solve it, I'm here
already, so I may as well stick around and go through it with you.


The sheet is telling you to find the solutions to two equations, AND THEN
DO SOMETHING WITH THE TWO SOLUTIONS.  But you've cut off the
instructions in the pictures, so all we have are the two equations, and
you'll have to figure out what to do with their solutions.

<u>First equation:</u>
                                   (2/5) x - 6 = -2
Add 6 to each side:
                                   (2/5) x = 4
Multiply each side by 5:
                                   2x = 20
Divide each side by 2 :
                                     <u>x = 10</u>

<u>Second equation:</u>
                                   -3y + 1/4 = 13/4
Subtract 1/4 from each side:
                                   -3y = 12/4
Multiply each side by 4 :
                                -12 y = 12
Divide each side by -12 :
                                      <u> y = -1</u>
5 0
3 years ago
Read 2 more answers
There are 11 students on the tennis team. The coach selects 3 of them to go to atennis clinic. In how many ways can he choose 3
Komok [63]

Answer:

165 ways

Step-by-step explanation:

Selection deals with combination

There are a total of 11 from which 3 are to be selected

        11C3 = 11!/3!(11-3)!

                 = 11!/(3!x8!)

                 =(11x10x9x8!)/(3x2x8!)

                 =11x10x9/6

                 =11x5x3 = 165 ways

                 

8 0
3 years ago
Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0
Softa [21]

The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

The equation of an ellipse centered at  (h,k) is

(x - h)²/a² + (y - k)²/b² (1) where a > b and the major axis is parallel to the x axis

Given x² + 16y² - 96y + 128 = 0, we convert it into the standard equation of an ellipse.

So, x² + 16y² - 96y + 128 = 0

Dividing through by 16, we have

x²/16 + 16y²/16  - 96y/16 + 128/16 = 0/16

x²/16 + y² - 6y + 8 = 0

Completing the square in y by adding and subtracting (-6/2)² = (-3)²

x²/16 + y² - 6y + (-3)² - (-3)² + 8 = 0

x²/16 + (y - 3)² - 9 + 8 = 0

x²/16 + (y - 3)² - 1 = 0

x²/16 + (y - 3)² = 1

x²/4² + (y - 3)²/1² = 1  (2)

Comparing equations (1) and (2), we have that a = 4 and b = 1.

Since a = 4 > b = 1, the major axis for the ellipse is the x-axis

So, the major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

Learn more about ellipse here:

brainly.com/question/26679189

#SPJ1

8 0
2 years ago
What is the maximum number of possible extreme values for the function, F(x)=x^4+x^3-7x^2-x+6?
Arturiano [62]

Coming from a 6th grader but I hope this is right!

Polynomials of degree greater than 2 can have more than one max or min value. The largest possible number of minimum or maximum points is one less than the degree of the polynomial. The following examples illustrate several possibilities.

since the degree is 4

number of possible extreme values = 4 -1 = 3

3 0
3 years ago
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